Q

# I need help with - Chemical Thermodynamics - JEE Main-2

In an irreversible process taking place at constant $T$ and $\dpi{100} P$ and in which only pressure-­volume work is being done, the change in Gibbs free energy $\dpi{100} (dG)$ and change in entropy $\dpi{100} (dS)$ , satisfy the criteria

• Option 1)

$(dS)_{V,E}< 0,(dG)_{T,P}< 0$

• Option 2)

$(dS)_{V,E}> 0,(dG)_{T,P}< 0$

• Option 3)

$(dS)_{V,E}= 0,(dG)_{T,P}= 0$

• Option 4)

$(dS)_{V,E}= 0,(dG)_{T,P}> 0$

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As we learnt in

Spontanous process -

$\Delta G= \Delta H-\Delta T$

- wherein

For spontanouse process $\Delta G$ must be negative.

For spontaneous reaction dS > 0 and dG should be negative i.e < 0

Option 1)

$(dS)_{V,E}< 0,(dG)_{T,P}< 0$

this is incorrect option

Option 2)

$(dS)_{V,E}> 0,(dG)_{T,P}< 0$

this is correct option

Option 3)

$(dS)_{V,E}= 0,(dG)_{T,P}= 0$

this is incorrect option

Option 4)

$(dS)_{V,E}= 0,(dG)_{T,P}> 0$

this is incorrect option

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