Q

# I need help with - Co-ordinate geometry - JEE Main

The equation of the circle, which is the mirror image of the circle,

• Option 1)

• Option 2)

• Option 3)

• Option 4)

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As learnt in

Equation of a circle -

$\left ( x-h \right )^{2}+\left ( y-k \right )^{2}= r^{2}$

- wherein

Circle with centre $\left ( h,k \right )$ and radius $r$.

General form of a circle -

$x^{2}+y^{2}+2gx+2fy+c= 0$

- wherein

centre = $\left ( -g,-f \right )$

radius = $\sqrt{g^{2}+f^{2}-c}$

Image of A in the line

x+y=3.

Equation of AB is

x-y=1

Coordinate of C: x+y=3

x-y=1

------------

x=2, y=1

$\frac{h+1}{2}=2,\:\frac{k}{2}=1$

h=3, k=2

Coordinates of B is (3,2) which is mirror image of centre (1,0) and radius is same =1

Hence equation is (x-3)2 + (y-2)2 = 1

x2+y2-6x-4y+12=0

Option 1)

This option is correct.

Option 2)

This option is incorrect.

Option 3)

This option is incorrect.

Option 4)

This option is incorrect.

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