Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

In common base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor (\beta ) will be

  • Option 1)

    48

  • Option 2)

    49

  • Option 3)

    50

  • Option 4)

    51

 

Answers (1)

best_answer

As we learnt in

Relation between emitter current ,Base current,collector current -

I_{E}= I_{B}+I_{C}
 

- wherein

I_{E}=Emitter\: Current

I_{B}= Base \: Current

I_{C}= Collector \: Current

 

 I_{E}=I_{C}+I_{B}

Here IE = 5.6 mA

    IC = 5.488 mA

\therefore\ \, I_{B}=I_{E}-I_{C}=0.112\ mA

Current amplification factor

\beta=\frac{I_{C}}{I_{B}}=\frac{5.488}{0.112}=49

Correct option is 2.

 


Option 1)

48

This is an incorrect option.

Option 2)

49

This is the correct option.

Option 3)

50

This is an incorrect option.

Option 4)

51

This is an incorrect option.

Posted by

prateek

View full answer

Crack JEE Main with "AI Coach"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
jee_ads

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2023 Admit Card Live: NTA JEE Mains Session 2 city intimation slip link at jeemain.nta.nic.in soon
anam-khan

JEE Main 2023 April Session: How e-libraries can help accelerate exam preparation
anam-khan

Fake videos on JEE Main 2023 session 2 admit card, city slip release date circulating, NTA warns

Latest Question