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Equation of sound wave is \Delta P = 0.02\sin[300t -9x] is given. Find the frequency of sound wave in air

  • Option 1)

    3000Hz

  • Option 2)

    \frac{2\pi}{3000}\; Hz

  • Option 3)

    \frac{3000}{2\pi}\; Hz

  • Option 4)

    \frac{1000}{3}\; Hz

 

Answers (1)

best_answer

Compare with standard eqn

\Delta p = \Delta p_{max} sin \left [ \omega \left ( t - \frac{x}{v} \right ) \right ]

\omega = 3000\Rightarrow f = \frac{\omega }{2 \pi} = \frac{3000}{2 \pi} Hz

 

Pressure Waves -

\Delta P= -\Delta P_{max}\cdot \cos \left ( Kx-\omega t \right )
 

- wherein

\Delta P_{max} = Maximum variation in pressure

 

 

 


Option 1)

3000Hz

This is incorrect.

Option 2)

\frac{2\pi}{3000}\; Hz

This is incorrect.

Option 3)

\frac{3000}{2\pi}\; Hz

This is correct.

Option 4)

\frac{1000}{3}\; Hz

This is incorrect.

Posted by

Avinash

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