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Mg + 2HCl \rightarrow MgCl_{2} + H_{2}

If 0.3 moles of Mg are added to HCl container having 0.5 mole HCl, how many moles of H2O are produced?

  • Option 1)

    0.5

  • Option 2)

    0.3

  • Option 3)

    0.25

  • Option 4)

    0.5

 

Answers (1)

best_answer

As we have learnt,

 

Concept of limiting reagent and excess reagent -

The reactant which gets consumed and thus limits the amount of product formed is called the limiting reagent.

- wherein

 CH4 (g) + 2O2 (g) → CO2 (g) + 2 H2O (g) ;

In this reaction, if 1 mole of methane and 1 mole of oxygen are taken then oxygen would be limiting reagent.

 

 

                                             Mg + 2HCl \rightarrow MgCl_{2} + H_{2}

Moles Before reaction:          0.3            0.5                0                 0

Moles After reaction:            0.05            0                0.25            0.25

\therefore moles of H2 produced = 0.25


Option 1)

0.5

Option 2)

0.3

Option 3)

0.25

Option 4)

0.5

Posted by

divya.saini

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