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The circuit shown below contains two ideal diodes, each with a forward resistance of 50\Omega. If the battery voltage is 6V, the current through the 100\Omega resistance(in Amperes) is:

 

 

  • Option 1)

     

    0.036

  • Option 2)

     

    0.020

     

  • Option 3)

     

    0.030

  • Option 4)

     

    0.027

Answers (1)

best_answer

 

P -N junction as diode -

It is a one way device. It offers a low resistance when forward biased and high resistance when reverse biased.

- wherein

R = 0, Forward 

\rightarrow \infty Reverse

 

In this situation 

D_{2} is in reverse bias

so no current will pass through

D_{2} & (75\Omega ) Resistance.

I=\frac{V}{R_{net}}=\frac{6}{100+50+150}=\frac{6}{300}

I=0.002 A

 


Option 1)

 

0.036

Option 2)

 

0.020

 

Option 3)

 

0.030

Option 4)

 

0.027

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