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The parallel combination of two air filled parallel plate capacitors of capacitance  C and nC is connected  to a battery of voltage , V . When the capacitors are fully charged , the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitors . The new potential difference of the combined system is :

  • Option 1)

    \frac{nV}{K+n}
     

  • Option 2)

    V

  • Option 3)

    \frac{V}{K+n}

     

  • Option 4)

    \frac{(n+1)V}{(K+n)}

Answers (1)

best_answer

\left ( C_{eq} \right )_{initially}={n}C+C=(n+1)C

Q=(n+1)C\:V

Q should be conserved after removal of battery 

\Rightarrow (C_{eq})_{final}=nC+kC=(n+k)C

\Rightarrow (n+k)C\:\:V_{final }=(n+1)C\:V

\Rightarrow \:V_{final }=\frac{n+1}{n+k}\:V


Option 1)

\frac{nV}{K+n}
 

Option 2)

V

Option 3)

\frac{V}{K+n}

 

Option 4)

\frac{(n+1)V}{(K+n)}

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