Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I need help with - Three Dimensional Geometry - JEE Main-2

If (2, 3, 5) is one end of a diameter of the sphere x^{2}+y^{2}+z^{2}-6x-12y-2z+20=0, then the coordinates of the other end of the diameter are

  • Option 1)

    (4, 3, 5)

  • Option 2)

    (4, 3, –3)

  • Option 3)

    (4, 9, –3)

  • Option 4)

    (4, –3, 3)

 

Answers (1)

best_answer

As we learnt in 

Section Formula -

1)    Internal Division

\left ( \frac{mx_{2}+nx_{1}}{m+n}, \frac{my_{2}+ny_{1}}{m+n}, \frac{mz_{2}+nz_{1}}{m+n} \right )

2)    External Division

\left ( \frac{mx_{2}-nx_{1}}{m-n}, \frac{my_{2}-ny_{1}}{m-n}, \frac{mz_{2}-nz_{1}}{m-n} \right )

3)    Mid Point Formula

\left ( \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}, \frac{z_{1}+z_{2}}{2} \right )

- wherein

 

 Coordinate of centre of sphere= (3,6,1)

Let other end be (x,y,z)

\frac{x+2}{2}= 3,\frac{y+3}{2}= 6,\frac{z+5}{2}= 1

x= 4, y= 9, z=-3


Option 1)

(4, 3, 5)

Incorrect Option

 

Option 2)

(4, 3, –3)

Incorrect Option

 

Option 3)

(4, 9, –3)

Correct Option

 

Option 4)

(4, –3, 3)

Incorrect Option

 

Posted by

Plabita

View full answer

Crack JEE Main with "AI Coach"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
jee_ads

Similar Questions

Trending Articles/News

anam-khan

JEE Main Cut Off 2023: NIT closing ranks for BTech electrical engineering
anam-khan

JEE Main 2023: IIT, NIT cut-off marks for BTech in artificial intelligence
anam-khan

JEE Main 2023 session 2 registration last date today; apply at jeemain.nta.nic.in

Latest Question