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  • I need help with Two blocks of masses 5kg and 10kg are connected to a pulley as shown in fig. What will be the acceleration if the pulley is set free?

Two blocks of masses 5kg and 10kg are connected to a pulley as shown in fig. What will be the acceleration if the pulley is set free?

  • Option 1)

    g

  • Option 2)

    g/2

  • Option 3)

    g/3

  • Option 4)

    g/4

 

Answers (2)

best_answer

As we learnt in

Motion of connected blocks over pulley -

Equation of motion for   m_{1}

F_{net}=T-m_{1}g=m_{1}a

Equation of Motion for   m_{2}

F_{net}=m_{2}g-T=m_{2}a

 

- wherein

a=\frac{[m_{2}-m_{1}\:]g}{m_{1}+m_{2}}

T=\frac{2m_{1}m_{2}\:g}{m_{1}+m_{2}}


 

a= g\frac{(m_2-m_1)}{(m_1+m_3)}=\frac{ag(10-5)}{10+5}  

a=\frac{5g}{15}

a= \frac{g}{3}


Option 1)

g

Incorrect

Option 2)

g/2

Incorrect

Option 3)

g/3

Correct

Option 4)

g/4

Incorrect

Posted by

prateek

View full answer

(M1-M2)G/M1+M2.     =10-5×g/10+5=5g/15=g/3

 

Option 3

Posted by

K nikil

View full answer

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