Which of the following atoms has the lowest ionization potential ?

  • Option 1)

    _{7}^{14}N

  • Option 2)

    _{55}^{133}Cs

  • Option 3)

    _{18}^{40}Ar

  • Option 4)

    _{8}^{16}O

 

Answers (1)

As we learnt in

Ionization energy -

E_{ion }= E_{\infty }-E_{n }

=13.6\frac{Z^{2}}{n^{2}}

 

- wherein

Energy required to move an electron from ground state to n= \infty

 

 

_{55}^{133}Cs has the lowest ionization potential. Of the four atoms given, Cs has the largest size. Electrons in the outer most orbit are at large distance from nucleus in a large­size atom. Hence the ionization potential is the least.

Correct option is 2.


Option 1)

_{7}^{14}N

This is an incorrect option.

Option 2)

_{55}^{133}Cs

This is the correct option.

Option 3)

_{18}^{40}Ar

This is an incorrect option.

Option 4)

_{8}^{16}O

This is an incorrect option.

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