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  • Identify the correct statement for from those given below. (

Identify the correct statement for \mathrm{B_{2}H_{6}} from those given below.

(A)  In \mathrm{B_{2}H_{6},} all \mathrm{B-H} bonds are equivalent.

(B)  In  \mathrm{B_{2}H_{6},}  there are four 3-centre-2-electron bonds.

(C)   \mathrm{B_{2}H_{6}}  is a Lewis acid.

(D)   \mathrm{B_{2}H_{6}}  can be synthesized from both \mathrm{BF_{3}}  and \mathrm{NaBH_{4}}.

(E)   \mathrm{B_{2}H_{6}}  is a planar molecule.

Choose the most appropriate answer from the options  given below :

Option: 1

\mathrm{(A)\, and\, (E)\, only}


Option: 2

\mathrm{(B)\,,(C) \, and\, (E)\, only}


Option: 3

\mathrm{(C)\, and\, (D)\, only}


Option: 4

\mathrm{(C)\, and\, (E)\, only}


Answers (1)

best_answer

As we have learnt,
Diborane is a non planar molecule with \mathrm{sp^{3}} hybridised Boron centres.

It is electron deficient and contains two \mathrm{3 c-2 e} bridge bonds. The structure iss given below :


All the B-H bonds are not equivalent as the two bridged bonds are electron deficient and weak.

Diborane can be synthesised from both \mathrm{\mathrm{BF}_{3}\:}  and  \mathrm{\mathrm{NaBH}_{4}}. The reactions are given below:

\mathrm{\mathrm{BF}_{3}+LiAlH_{4} \rightarrow \mathrm{B}_{2} \mathrm{H}_{6}+\mathrm{LiF}+\mathrm{Al} \mathrm{F}_{3}}

\mathrm{\mathrm{NaBH_{4}}+\mathrm{I}_{2} \longrightarrow \mathrm{B}_{2} \mathrm{H}_{6}+\mathrm{NaI}+\mathrm{H}_{2}}

Hence, the correct answer is Option (3)

Posted by

Pankaj Sanodiya

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