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  • Identify the process in which change in the oxidation state is five :Option: 1 <img alt="\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} \rightarrow 2 \mathrm{Cr}^{3+}" src="https://entrancecorner.codecogs.com/gif.latex?%5Cmathrm%7BCr%7D_%7B2%7D%20%5Cmath

Identify the process in which change in the oxidation state is five :
Option: 1 \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} \rightarrow 2 \mathrm{Cr}^{3+}
Option: 2 \mathrm{MnO}_{4}^{-} \rightarrow \mathrm{Mn}^{2+}
Option: 3 \mathrm{CrO}_{4}^{2-} \rightarrow \mathrm{Cr}^{3+}
Option: 4 \mathrm{C}_{2} \mathrm{O}_{4}^{2-} \rightarrow 2 \mathrm{CO}_{2}

Answers (1)

best_answer

The change in the onidation states in the reactions is

Cr_{2}O_{7}\, ^{2-}\rightarrow 2Cr^{3+};\: \Delta = 3
\left ( +6 \right )                   \left ( +3 \right )
MnO_{4} ^{-}\rightarrow Mn^{2+};\: \Delta = 5
\left ( +7 \right )                 \left ( +2 \right )
CrO_{4}\, ^{2-}\rightarrow Cr^{3+};\: \Delta = 3
\left ( +6 \right )                   \left ( +3 \right )
CrO_{4}\, ^{2-}\rightarrow 2CO_{2};\: \Delta =1   
\left ( +3 \right )                   \left ( +4 \right )

Hence, the correct answer is option (2)

Posted by

sudhir.kumar

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