If a , b, c are in AP, then which of the following are also in A.P.
None of these
Method 1:
As a,b,c are in A.P multipling each term by (-1) will give a new AP so, -a,-b, -c are in AP.
Now adding (a+b+c) to each term will give a new AP
So, are in AP
is an AP
Method 2:
To prove A,B,C in AP we need to prove that 2B -(A+C) =0
So for option (A)
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