If a certain amount of slaked lime (Ca(OH)2) on heating gave 33.6 L of H2O vapour at STP, then what is the number of moles of slaked lime we had?

 

Answers (1)

Number of Moles of a gas at STP -

no of moles of a gas at STP= given volume of gas / 22.4 liter

 Ca(OH)_{2}\rightarrow CaO+H_{2}O

\therefore \: 1 \: mole\: o\! f Ca(OH)_{2}\: Gives\: 1 \: mole\: of\: H_{2}O

\therefore \: 1.5 \: mole\: o\! f Ca(OH)_{2}\: Gives\: 1.5 \: mole\: of\: H_{2}O

 

Moles of H2O =\frac{33.6}{22.4}= 1.5

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