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If a radioactive element having half-life of 30 min is undergoing beta decay, the fraction of radioactive element remains undecayed after 90 min. will be

Option: 1

\frac{1}{8}


Option: 2

\frac{1}{4}


Option: 3

\frac{1}{2}


Option: 4

\frac{1}{16}


Answers (1)

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\begin{aligned} & \mathrm{T}=30 \mathrm{~min} \\ & \mathrm{t}=90 \mathrm{~min} \\ & \mathrm{n}=\frac{\mathrm{t}}{\mathrm{T}}=\frac{90 \mathrm{~min}}{30 \mathrm{~min}}=3 \\ & \mathrm{~N} \text { (active) }=\frac{\mathrm{N}_0}{2^{\mathrm{n}}}=\frac{\mathrm{N}_0}{2^3}=\frac{\mathrm{N}_0}{8} \end{aligned}

\frac{N}{N_o}=\frac{1}{8}

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Ritika Kankaria

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