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  • If a semiconductor photodiode can detect a photon with a maximum wavelength of , then its band gap energy (in eV) is : Planck's constant  

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400\; nm, then its band gap energy (in eV) is : Planck's constant  h=6.63\times 10^{-34}J.s. Speed of light c=3\times 10^{8}\; m/s
Option: 1 3.1
Option: 2 2.0
Option: 3 1.5
Option: 4 1.1

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\begin{aligned} &\text { For photodiode to detect } \\& E=\frac{hc}{ \lambda}>(\text { band gap energy })\\ &\Rightarrow( \text { band gap energy })_{max}= \mathrm{hc} / \lambda_{\max } \\ &=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{400 \times 10^{-9}}=5 \times 10^{-19} \mathrm{~J}=3.1 \mathrm{eV} \end{aligned}

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