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  • If a set of 9 orange, 4 blue, and 5 green bangles is available, how many different ways are there in which one or more of the rings can be selected?aOption: 1</s

If a set of 9 orange, 4 blue, and 5 green bangles is available, how many different ways are there in which one or more of the rings can be selected?a

Option: 1

290


Option: 2

315


Option: 3

299

 


Option: 4

405


Answers (1)

best_answer

Given that,

The different types of rings are 9 orange bangles, 4 blue bangles, and 5 green bangles.

The total number of rings is 18 bangles.

The number of orange bangles = 9.

The number of blue bangles  = 4.

The number of green bangles = 5.

The formula to find the number of ways of selection is given by,

\begin{aligned} & N=(p+1) \times(q+1) \times(r+1)-1 \\ & N=(9+1) \times(4+1) \times(5+1)-1 \\ & N=(10 \times 5 \times 6)-1 \\ & N=300-1 \\ & N=299 \end{aligned}

Therefore, the number of ways of arranging the rings is 299 ways.

 

Posted by

Sanket Gandhi

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