Get Answers to all your Questions

header-bg qa

If a zener diode  and \mathrm{\left(\mathrm{V}_{\mathrm{Z}}=5 \mathrm{~V} \text { and } \mathrm{I}_{\mathrm{Z}}=10 \mathrm{~mA}\right)} is connected in series with a resistance and 20 \mathrm{~V} is applied across the combination, then the maximum resistance one can use without spoiling zener action is

Option: 1

20 \mathrm{k} \Omega


Option: 2

15 \mathrm{k} \Omega


Option: 3

10 \mathrm{k} \Omega


Option: 4

1.5 \mathrm{k} \Omega


Answers (1)

best_answer

Voltage available across load resistance
\mathrm{R=20-5=15 \mathrm{~V}}
Resistance of load,

\mathrm{\begin{aligned} & R=\frac{15}{10 \times 10^{-3}}=1.5 \times 10^3 \\ & =1.5 \mathrm{k} \Omega \end{aligned}}

Posted by

HARSH KANKARIA

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE