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If an electron and a proton having the same momenta, enter perpendicularly to a uniform magnetic field, then

Option: 1

both will have the same curved path (ignoring the sense of revolution)


Option: 2

they will move undeflected
 


Option: 3

the path of the electron will be move curved than that of the proton
 


Option: 4

the path of the proton is more curved.
 


Answers (1)

best_answer

The radius of the circular path is
\mathrm{r=\frac{m v}{q B} \Rightarrow r=\frac{p}{q B} ; \quad p=m v .}
Since p, q, B are the same for electron and proton, the value of r will be the same for both. Since the charge of an electron is opposite in sign to that of proton, the sense of revolution will be opposite. So the correct choice is (a).

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avinash.dongre

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