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If  \mathrm{ f^{\prime}(a)=2}  and f(a)=4, then \mathrm{ \lim _{x \rightarrow a} \frac{x f(a)-a f(x)}{x-a}}  equals

Option: 1

2 a-4


Option: 2

4-2 a


Option: 3

2 a+4


Option: 4

none of these


Answers (1)

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\mathrm{ \lim _{x \rightarrow a} \frac{x f(a)-a f(x)}{x-a} \\ }

\mathrm{ =\lim _{x \rightarrow a} \frac{x f(a)-a f(a)-a(f(x)-f(a)}{x-a} \\ }

\mathrm{ =\lim _{x \rightarrow a} \frac{f(a)(x-a)}{x-a}-a \lim _{x \rightarrow a} \frac{f(x)-f(a)}{x-a} \\ }

\mathrm{ =f(a)-a f^{\prime}(a)=4-2 a . }

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himanshu.meshram

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