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If compound \mathrm{A} reacts with \mathrm{B} following first order kinetics with rate constant \mathrm{2.011 \times 10^{-3} s^{-1}}. The time taken by A (in seconds) to reduce from \mathrm{7 g\: to\: 2 g} will be (Nearest Integer)
\mathrm{[log 5 = 0.698, log 7 = 0.845, log 2 = 0.301]}
 

Option: 1

623


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{For \: I^{st}order:-}

\mathrm{t=\frac{1}{2.011\times 1^{-3}}\times 2.303\times log\frac{7}{2}}

=\frac{2.303\times \left ( 0.845-0.301 \right )}{2.011\times 10^{-3}}

=622.9\approx 623

Posted by

Gautam harsolia

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