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If each digit can be repeated, how many different 3-digit numbers can be created using the digits 1, 2, 3, and 4?

 

Option: 1

36


Option: 2

49


Option: 3

81


Option: 4

64


Answers (1)

best_answer

Given that, 

The given digits are 1,2, 3, and 4. We have to create a 3-digit number.

The unit place can be filled by any one of the digits 1,2,3, and 4. So, the unit place can be filled in 4 ways.

The ten’s place can be filled by any one of the digits 1,2,3, and 4. So, the unit place can be filled in 4 ways.

The hundreds place can be filled by any one of the digits 1,2,3, and 4. So, the unit place can be filled in 4 ways. 

Thus, the total number of 3-digit numbers can be formed by,

4 \times 4 \times 4=64

Therefore, the total number of 3-digit numbers can be formed in 64 ways.

 

Posted by

Nehul

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