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If each diode has a forward bias resistance of $25 \; \Omega$ in the below circuit,

Which of the following options is correct:
Option: 1
$\frac{I_1}{I_2}=2$

Option: 2
$\frac{I_2}{\mathrm{I}_3}=1$

Option: 3
$\frac{\mathrm{I}_3}{\mathrm{I}_4}=1$

Option: 4
$\frac{I_1}{\mathrm{I}_2}=1$

Answers (1)

best_answer

Here we can see that $D_{1}$ and $D_{3}$ conducts but $D_{2}$ is reversed biased.
Current $I_{1}$ will be equally distributed among $I_{3}$ and $I_{4}$ and $I_{3}=0$

$\begin{aligned} & \mathrm{I}_1=\mathrm{I}_2+\mathrm{I}_4+\mathrm{I}_3 \\ & \mathrm{I}_1=2 \mathrm{I}_2 \\ & \frac{\mathrm{I}_1}{\mathrm{I}_2}=2 \end{aligned}$

Posted by

himanshu.meshram

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