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  • If elements with principal quantum number n > 4 were not allowed in nature, then the number of possible elements would be:Option: 1 32<b

If elements with principal quantum number n > 4 were not allowed in nature, then the number of possible elements would be:

Option: 1

32


Option: 2

60


Option: 3

18


Option: 4

4


Answers (1)

best_answer

If all the elements having n > 4 are removed the number of elements that will be present in the periodic table are calculated as

n = 1, represents K shell and the number of elements having K shell = 2 [in accordance with 2 n^2 ]

n = 2, represents L shell and the number of elements having L shell = 8

n = 3, represents M shell and the number of elements having M shell = 18

n = 4, represents N shell and the number of elements having N shell = 32

So, the total number of elements having n < 5 are 2 + 8 + 18 + 32 = 60

Posted by

jitender.kumar

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