# If the error in measurement of the diameter of the circle is 4%, then what is the error in measuring the circumference of the circle

As we learned,

The percentage error in the value of x -

$\dpi{100} x= \frac{\left ( \Delta a+\Delta b \right )}{a+b}\times 100\%$

- wherein

$\dpi{100} \Delta a$= absolute error in measurement of a

$\dpi{100} \Delta b$= absolute error in measurement of b

$\dpi{100} \Delta x$= absolute error in measurement of x

$D\propto r$  therefore there will be no change in error, it will remain 4% for radius also.

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