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If force (F), length (L) and time (T) are taken as the fundamental quantities. Then what will be the dimension of density:
 
Option: 1 \left[\mathrm{FL}^{-3}\mathrm{~T}^{3}\right]
Option: 2 \left[\mathrm{FL}^{-4} \mathrm{~T}^{2}\right]
Option: 3 \left[\mathrm{FL}^{-5}\mathrm{~T}^{2}\right]
Option: 4 \left[\mathrm{F} L^{-3} \mathrm{~T}^{2}\right]

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Let density  \alpha \: F^{x}\: L^{y}\: T^{z}\\

\left [ Density \right ]= \left [ F \right ]^{x}\left [ L \right ]^{y}\left [ T \right ]^{z}\\

                    = \left [ M^{1}L^{1}T^{-2} \right ]^{x}\left [ L \right ]^{y}\left [ T \right ]^{z}\\

\left [ M^{1}L^{-3}T^{0} \right ]= \left [ M^{x}L^{x+y}T^{-2x+z} \right ] \\

x= 1\\              ...........(1)

x+y= -3\\

y= -4\\          ...........(2)

-2x+z= 0\\

z= 2\\              ...........(3)

\left [ Density \right ]= \left [ F^{1}L^{-4}T^{2} \right ]

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vishal kumar

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