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  • If f(x) satisfies conditions of Rolle's theorem in [1,2] and f(x) is continuous in [1,2], then <img alt="\mathrm{\int_1^2 f^{\prime}(x) d x }" src="https://entrancecorner.oncodecogs.com/gif.lat

If f(x) satisfies conditions of Rolle's theorem in [1,2] and f(x) is continuous in [1,2], then \mathrm{\int_1^2 f^{\prime}(x) d x } is equal to

Option: 1

1


Option: 2

0.5


Option: 3

0


Option: 4

2


Answers (1)

best_answer

It is given that f(x) is continuous on [1,2], differentiable on (1,2) and f(2)=f(1).

\mathrm{\therefore \int_1^2 f^{\prime}(x) d x=[f(x)]_1^2=f(2)-f(1)=0 }
 

Posted by

sudhir.kumar

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