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  • If is the area in the first quadrant enclosed by the curve <img alt="C: 2 x^{2}-y+1=0" src="https://entrancecorner.oncodecogs

If A is the area in the first quadrant enclosed by the curve C: 2 x^{2}-y+1=0,the tangent to C at the point (1,3) and the line x+y=1, then the value of 60 \mathrm{~A} is _______.

Option: 1

16


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)


y=2 x^{2}+1
Tangenet at (1,3)

y=4 x-1
\mathrm{A}=\int_{0}^{1}\left(2 \mathrm{x}^{2}+1\right) \mathrm{dx}$ - area of $(\Delta \mathrm{QOT})- area \; of
(\triangle \mathrm{PQR})+$ area of $(\triangle \mathrm{QRS})
\mathrm{A}=\left(\frac{2}{3}+1\right)-\frac{1}{2}-\frac{9}{8}+\frac{9}{40}=\frac{16}{60}

Posted by

Ramraj Saini

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