Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr's first postulate, the kinetic energy

If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr's first postulate, the kinetic energy \mathrm{K= \frac{1}{2}mv^{2}}of the electron in C.G.S. system is equal to

Option: 1

\mathrm{\frac{1}{2}\frac{Ze^{2}}{r}}


Option: 2

\mathrm{\frac{1}{2}\frac{Ze^{2}}{r^{2}}}


Option: 3

\mathrm{\frac{Ze^{2}}{r}}


Option: 4

\mathrm{\frac{Ze}{r^{2}}}


Answers (1)

best_answer

In the revolution of electron, coulomb force provides the necessary centripetal force

\mathrm{\Rightarrow \frac{z e^2}{r^2}=\frac{m v^2}{r} \Rightarrow m v^2=\frac{z e^2}{r} }
\mathrm{\therefore \text { K.E. }=\frac{1}{2} m v^2=\frac{z e^2}{2 r} }

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024: NTA debars 39 candidates for 3 years on account of using unfair means
anam-khan

JEE Main 2024 session 2 paper 2 answer key objection window closes today; fees
anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’

Latest Question