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  • If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr's first postulate, the kinetic energy <img alt="\mathrm{K= \f

If m is mass of electron, v its velocity, r the radius of stationary circular orbit around a nucleus with charge Ze, then from Bohr's first postulate, the kinetic energy \mathrm{K= \frac{1}{2}mv^{2}}of the electron in C.G.S. system is equal to

Option: 1

\mathrm{\frac{1}{2}\frac{Ze^{2}}{r}}


Option: 2

\mathrm{\frac{1}{2}\frac{Ze^{2}}{r^{2}}}


Option: 3

\mathrm{\frac{Ze^{2}}{r}}


Option: 4

\mathrm{\frac{Ze}{r^{2}}}


Answers (1)

best_answer

In the revolution of electron, coulomb force provides the necessary centripetal force

\mathrm{\Rightarrow \frac{z e^2}{r^2}=\frac{m v^2}{r} \Rightarrow m v^2=\frac{z e^2}{r} }
\mathrm{\therefore \text { K.E. }=\frac{1}{2} m v^2=\frac{z e^2}{2 r} }

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Sayak

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