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If NaOH is added to an aqueous solution of zinc ions, a white precipitate appears and on adding excess NaOH, the precipitate dissolves. In this solution zinc exists in the

Option: 1

Cationic part


Option: 2

Anionic part


Option: 3

Both in cationic and anionic parts


Option: 4

There is no zinc in the solution


Answers (1)

best_answer

\mathrm{Zn ^{2+}} ions form a white precipitate of \mathrm{Zn(OH)_2} which on reaction with the excess of the reagent dissolves forming a complex \mathrm{Na_2[Zn(OH)_4]}.

The reactions are given as 

\mathrm{Zn ^{2+}+2 NaOH \rightarrow Zn ( OH )_{2}+2 Na ^{+}}

\mathrm{Zn ( OH )_{2}+2 NaOH \rightarrow Na _{2} [Zn(OH) _{4}]}

Hence, the correct answer is Option (2)

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