Get Answers to all your Questions

header-bg qa

If the binding energy of ground state electron in a hydrogen atom is 13.6 \mathrm{eV}, then, the energy required to remove the electron from the second excited state of \mathrm{Li}^{2+}will be : x \times 10^{-1} \mathrm{eV}. The value of x is _____.

Option: 1

136


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{BE}=13.6 \times \frac{\mathrm{z}^{2}}{\mathrm{n}^{2}}
\mathrm{BE}=13.6 \times\left(\frac{3}{3}\right)^{2}=13.6 \mathrm{eV}
\mathrm{BE}=136 \times 10^{-1} \mathrm{eV}
\mathrm{x}=136

Posted by

himanshu.meshram

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE