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If the bulk modulus of water is 6400 \mathrm{MPa}, what is the speed of sound in water?

Option: 1

2345 m/s


Option: 2

4356 m/s


Option: 3

2528 m/s


Option: 4

2879 m/s


Answers (1)

best_answer

speed of sound in water is v=\sqrt{\frac{B}{p}}

Where B is the bulk modulus and P is the density of water.

Here, B=6400 \mathrm{MPa}

B =6400 \times 10^6 \mathrm{~Pa} \\

P =10^3 \mathrm{~kg} / \mathrm{m}^3 \\

\therefore \quad V =\sqrt{\frac{6400 \times 10^6}{10^3}} \\

V =\frac{{\sqrt{64} \times \sqrt{10} \times \sqrt{106}}}{\sqrt{10^2}}
V=\frac{8 \times 10^3}{10} \times \sqrt{10} =800 \times \sqrt{10} \\

V=800 \times 3.16 =2528 \mathrm{~m} / \mathrm{s}

Posted by

Deependra Verma

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