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If the concentration of glucose \left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)in blood is 0.72 \mathrm{~g} \mathrm{~L}^{-1}, the molarity of glucose in blood is ____\times 10^{-3} \mathrm{M}. (Nearest integer) [Given : Atomic mass of \mathrm{C}=12, \mathrm{H}=1, \mathrm{O}=16 \mathrm{u}]
 

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best_answer

Given,

Concentration of Glucose \mathrm{= 0.72 \; g\; L^{-1}}

Thus, 1 litre glucose solution contains 0.72 g

\therefore \text { Molarity }=\frac{0.72}{180 \times 1}=4 \times 10^{-3} \mathrm{~M}

Hence, the correct answer is 4

Posted by

sudhir.kumar

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