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If the mirror image of the point (2,4,7) in the plane \mathrm{3 x-y+4 z=2} is \mathrm{(a, b, c),} then \mathrm{2 a+b+2 c} is equal to :

Option: 1

54


Option: 2

50


Option: 3

-6


Option: 4

-42


Answers (1)

best_answer

Using formula for mirror image

\mathrm{\frac{a-2}{3}=\frac{b-4}{-1}=\frac{c-7}{4}=\frac{-2(6-4+28-2)}{9+1+16} }\\

\mathrm{\frac{a-2}{3}=\frac{b-4}{-1}=\frac{c-7}{4}=-\frac{1}{13}(28)}

\mathrm{a=2 -\frac{28 \times 3}{13}=\frac{-58}{13}} \\

\mathrm{b=4+\frac{28}{13}=\frac{80}{13}} \\

\mathrm{c=7-\frac{28 \times 4}{13}=-\frac{21}{13}} \\

\mathrm{\therefore 2 a+b+2 c=\frac{-116}{13}+\frac{80}{13}-\frac{42}{13} }\\

                           \mathrm{=-\frac{78}{13}=-6}

Hence answer is option 3.

Posted by

Rakesh

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