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If the potential barrier across a p-n junction is 0.6 \mathrm{~V}. Then the electric field intensity, in the depletion region having the width of 6 \times 10^{-6} \mathrm{~m}, will be_________ \times 10^{5} \mathrm{~N} / \mathrm{C}

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\Delta V=0.6 \mathrm{~V} }

\mathrm{d=6 \times 10^{-6} \mathrm{~m} }

\mathrm{E=\frac{\Delta V}{d}=\frac{0.6}{6 \times 10^{-6}}=\frac{6 \times 10^5}{6} }

\mathrm{E=1 \times 10^5 \mathrm{~N} / \mathrm{C} }


 

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