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If the ratio of the concentration of electrons to that of holes in a semiconductor is \frac{7}{5} and the ratio of currents is \frac{7}{4}, , then what is the ratio of their drift velocities?

Option: 1

\mathrm{\frac{5}{8}}


Option: 2

\mathrm{\frac{4}{5}}


Option: 3

\mathrm{\frac{5}{4}}


Option: 4

\mathrm{\frac{4}{7}}


Answers (1)

best_answer

\mathrm{ \frac{\mathrm{I}_e}{\mathrm{l}_{\mathrm{b}}}=\frac{\mathrm{n}_{\mathrm{e}} \mathrm{CAv_{ \textrm {e } }}}{\mathrm{B}_{\mathrm{h}} \mathrm{CAv_{ \textrm {h } }}} \Rightarrow \frac{7}{4}=\frac{7}{5} \times \frac{\mathrm{v}_{\mathrm{e}}}{\mathrm{v}_{\mathrm{b}}} \Rightarrow \frac{\mathrm{v}_{\mathrm{e}}}{\mathrm{v}_{\mathrm{h}}}=\frac{5}{4} }

Posted by

Kuldeep Maurya

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