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If the screw on the screw-gauge is given six rotations, it moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is: (in cm)   
Option: 1 0.001
Option: 2 0.01
Option: 3 0.02
Option: 4 0.001
 

Answers (1)

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Pitch =\frac{3}{6} = 0.5mm

L.C = \frac{0.5mm}{50} = \frac{1}{100}mm = 0.01mm = 0.001cm

Hence the option correct option is (1).  

Posted by

avinash.dongre

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