Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • If the value of Avogadro number is <img alt="6.023 \times 10^{23} \mathrm{~mol}^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?6.023%20%5Ctimes%2010%5E%7B23%7D%20%5Cmathrm%7B%7Emol

If the value of Avogadro number is 6.023 \times 10^{23} \mathrm{~mol}^{-1}  and the value of Boltzmann constant is  1.380 \times 10^{-23} \mathrm{Jk}^{-1}  then the numbers of significant digits in the calculated value of the universal gas constant is -

Option: 1

6


Option: 2

3


Option: 3

4


Option: 4

2


Answers (1)

best_answer

Universal gas constant, \mathrm{R=K N_A} 

where, k= Boltzmann constant

\mathrm{N_A}= Avogadro's numbers

\mathrm{R=1.380 \times 10^{-23} \times 6.023 \times 10^{23} \mathrm{~J} / \mathrm{kmol}}

\mathrm{=8.31174 \approx 8.312}

\mathrm{\approx 8.312}
Since, k and \mathrm{N_A}  both have four significant figures, so the value of R is also rounded off up to 4 significant figures.

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech CSE cut-offs for PwD candidates at NITs make entry easy; top institutes still selective
anam-khan

73 or 99 percentile? JEE Main result questioned, J-K candidate says, ‘Don’t create hype’
anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile

Latest Question