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  • If the volume of closed vessel in which the following simple reaction is carried out is reduced to one-third of the original volume, the rate of reaction becomes <img alt="2 \mathrm{NO}(\mat

If the volume of closed vessel in which the following simple reaction is carried out is reduced to one-third of the original volume, the rate of reaction becomes
2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_2(\mathrm{~g}) \longrightarrow 2 \mathrm{NO}_2(\mathrm{~g}).

Option: 1

1/27 Times
 


Option: 2

3 Times


Option: 3

3/2 Times


Option: 4

27 Times
 


Answers (1)

best_answer

Rate \mathrm{ \mathrm{r}_1=\mathrm{K}[\mathrm{NO}]^2\left[\mathrm{O}_2\right]}
On reducing the vessel volume by one-third, the concentration of each reactant increases by three times.
Rate \mathrm{\mathrm{r}_2=\mathrm{K}[3 \mathrm{NO}]^2\left[3 \mathrm{O}_2\right]}

\mathrm{=27 \mathrm{~K}[\mathrm{NO}]^2\left[\mathrm{O}_2\right]}

\mathrm{=27 \mathrm{r}_1}

Posted by

Shailly goel

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