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If the wavelength of an electron is 0.1 nm, what is its momentum?

Option: 1

6.6\times 10^{-26}kg\, m/s


Option: 2

6.6\times 10^{-25}kg\, m/s


Option: 3

6.6\times 10^{-24}kg\, m/s


Option: 4

6.6\times 10^{-23}kg\, m/s


Answers (1)

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De Broglie's hypothesis states that matter also has both particle and wave nature, and he proposed an equation to calculate the wavelength associated with a moving material particle of momentum. The wavelength is given by the equation \lambda= \frac{h}{p}, where h is Planck's constant.According to De Broglie’s equation, the wavelength associated with a moving material particle of momentum p is given as \lambda= \frac{h}{p}.
Rearranging the equation gives p= h/\lambda. Substituting h= 6.626 \times 10^{-34} Js and \lambda= 0.1nm= 10^{-10}m  in the equation gives p= 6.6\times 10^{-23}kg\, m/s.

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