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  • If two charges  and <img alt="q_{2}" src="https://entrancecorner.oncodecogs.com/gif.latex?q_%7B2%7D

If two charges q_{1} and q_{2} are separated with distance 'd' and placed in a medium of dielectric constant K. What will be the equivalent

distance between charges in air for the same electrostatic force? 

Option: 1

2 \mathrm{~d} \sqrt{\mathrm{k}}


Option: 2

1.5 \mathrm{~d} \sqrt{\mathrm{k}}


Option: 3

\mathrm{d} \sqrt{\mathrm{k}}


Option: 4

k \sqrt{d}


Answers (1)

best_answer

\frac{\mathrm{q}_1 \mathrm{q}_2}{4 \pi \varepsilon_0 \mathrm{kd}^2}=\frac{\mathrm{q}_1 \mathrm{q}_2}{4 \pi \varepsilon_0 \mathrm{r}^2} \Rightarrow \mathrm{r}=\mathrm{d} \sqrt{\mathrm{K}}

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Gunjita

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