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If x2 + y2 = 1, then

Option: 1

yy" – (2y')2 + 1 = 0


Option: 2

yy" + (y')2 + 1 = 0

 


Option: 3

yy" – (y')2 – 1 = 0


Option: 4

yy" + 2(y')2 + 1 = 0


Answers (1)

best_answer

\begin{aligned} & y^2=1-x^2 \Rightarrow 2 y y^{\prime}=-2 x \\ & \Rightarrow y y^{\prime}=-x \Rightarrow y y^{\prime \prime}+y^{\prime}+y^{\prime}=-1 \\ & \Rightarrow y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0 \end{aligned}

Hence (B) is correct answer.

 

Posted by

shivangi.bhatnagar

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