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  • If you are provided a set of resistances <img alt="2\, \Omega ,4\, \Omega ,6\, \Omega \, and\, 8\, \Omega." src="https://entrancecorner.codecogs.com/gif.latex?2%5C%2C%20%5COmega%20%2C4%5C%2C%20%5COmega%20%2C6%5C%2C%20%5COmega%20%5C%2C%20and%5C%2C%208%5C%2

If you are provided a set of resistances 2\, \Omega ,4\, \Omega ,6\, \Omega \, and\, 8\, \Omega. Connect these resistances so as to obtain an equivalent resistances of \frac{46}{3} \Omega.
Option: 1 2\: \Omega and 6\: \Omega are in  parallel with 4\: \Omega and 8\: \Omega in series
Option: 2 4\: \Omega and 6\: \Omega are in  parallel with 2\: \Omega  and  8\: \Omega in series
Option: 3 2\: \: \Omega and 4\: \: \Omega are in parallel with 6\: \: \Omega and 8\: \: \Omega in series
Option: 4 6\: \Omega and 8\: \Omega are in parallel with 2\: \Omega and 4\: \Omega in series

Answers (1)

best_answer


R_{eq}= \frac{2\times4}{2+4}+6+8
        = \frac{8}{6}+6+8= \frac{4}{3}+14
R_{eq}= \frac{46}{3}
The correct option is (3)

Posted by

vishal kumar

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