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2 \mathrm{~N}_2 \mathrm{O}_5 \rightarrow 4 \mathrm{NO}_2+\mathrm{O}_2, the rate equation can be expressed in twoways\frac{-d\left(\mathrm{~N}_2 \mathrm{O}_5\right]}{d t}-a\left[\mathrm{~N}_2 \mathrm{O}_5\right] and +\frac{d\left[\mathrm{NO}_2\right]}{d t}=a^{\prime}\left[\mathrm{N}_2 \mathrm{O}_5\right], what will be a and \mathrm{a^{\prime}} related as

Option: 1

\mathrm{2 a=a^{\prime}}


Option: 2

\mathrm{ a=a^{\prime}}


Option: 3

\mathrm{ a=6a^{\prime}}


Option: 4

\mathrm{a=4a^{\prime}}


Answers (1)

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Rate of dissapearence of rectant = Rate of apearence of products

\mathrm{\begin{aligned} & -\frac{1}{2} \frac{d\left[N_2 O_5\right]}{d t}=\frac{1}{4} \frac{d\left[\mathrm{NO}_2\right)^{\prime}}{d t} \\ & \frac{1}{2} a\left[\mathrm{~N}_2 \mathrm{O}_5\right]=\frac{1}{4} a^{\prime}\left[\mathrm{N}_2 \mathrm{O}_5\right] \\ & \frac{a}{2}=\frac{a^{\prime}}{4} \\ & a^{\prime}=2 a \end{aligned}}

 

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Shailly goel

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