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  • <img alt="\begin{aligned} &{\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}} \\ &{\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}} \\ &{\left[\mathrm{Ti}(\mathrm{CN})_{6}\right]^{3-}} \\

\begin{aligned} &{\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}} \\ &{\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}} \\ &{\left[\mathrm{Ti}(\mathrm{CN})_{6}\right]^{3-}} \\ &{\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}} \\ &{\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}} \end{aligned}

Among the given complexes, number of paramagnetic complexes is____________.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-} - is diamagnetic

\mathrm{\left [ Fe\left ( CN \right )_{6} \right ]^{3-}} - is paramagnetic with 1 unpaired \text{e}^{-}

\mathrm{[Ti(\mathrm{CN})_{6}]^{-3} - is paramagnetic  with 1 unpaired \text{e}^{-}

\mathrm{[\mathrm{Ni}(\mathrm{CN})_{4}]^{2-} - is diamagnetic

\mathrm{[Co(\mathrm{CN})_{6}]^{3-}} - is diamagnetic

Thus, out of the given complexes, only 2 are paramagnetic.

Hence, 2 is the answer

Posted by

Riya

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