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\mathrm{\begin{aligned} & P_2(g)+Q_2(g) \stackrel{R_1}{=} 2 P Q(g) \cdots(1) \\ & 6 P Q(g) \stackrel{R_2}{=} 3 P_2(g)+3 Q_2(g) \cdots(2) \end{aligned}}

Consider the following reversible chemical reaction, What will be the relation between \mathrm{R_1} and \mathrm{R_2}

Option: 1

\mathrm{R_1 R_2=1 / 4}


Option: 2

\mathrm{R_2=R_1^{-3}}


Option: 3

\mathrm{R_1 R_2=3}


Option: 4

\mathrm{R_2=R_1^3}


Answers (1)

best_answer

\mathrm{\begin{aligned} & P_2+Q_2=2 P Q \\ & R_1=\frac{[P Q]^2}{\left[P_2\right]\left[Q_2\right]} \\ & 6 P Q \rightleftharpoons 3 P_2+3 Q_2 \\ & R_2=\frac{\left[P_2\right]^3\left[Q_2\right]^3}{[P Q]^6} \\ & \text { so; } \frac{1}{R_1^3}=R_2 \\ & R_2=R_1^{3} \end{aligned}}

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Rishabh

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