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\mathrm{f(x)=1+[\cos x] x, \text { in } 0<x \leq \frac{\pi}{2}}

Option: 1

is continuous in \mathrm{\left[0, \frac{\pi}{2}\right]}


Option: 2

has a maximum value 2

 


Option: 3

has a minimum value 0


Option: 4

 is not differentiable at  x=\frac{\pi}{2}


Answers (1)

best_answer

Since f(x)=1 in \mathrm{0<x \leq \frac{\pi}{2} \quad[\mathrm{Q}[\cos x]=0]} 

\mathrm{\therefore f(x)} is continuous in  \mathrm{[0,\frac{\pi}{2}]}

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