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  • <img alt="\mathrm{f(x)=\left\{\begin{array}{cc} \min \left\{x, x^2\right\} & x \geq 0 \\ \min \left\{2 x,\left(x^2-1\right)\right\} & x<0 \end{array}\right.}" src="https://entrancecorner

\mathrm{f(x)=\left\{\begin{array}{cc} \min \left\{x, x^2\right\} & x \geq 0 \\ \min \left\{2 x,\left(x^2-1\right)\right\} & x<0 \end{array}\right.}

Then the number of points in the interval [-2,2] where f is non-differentiable, is 

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

best_answer

The graph of  the  function is 

From the graph, it is clear that f is non-differentiable at three points namely x=1-\sqrt{ } 2,0,1.

Posted by

manish painkra

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