Study 40% syllabus and score up to 100% marks in JEE
50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
JEE Main 2025: NIT Tiruchirappalli cut-offs rose for major BTech programmes this year; closing ranks
JoSAA 2025 reconstituted; NIT Rourkela to coordinate BTech counselling for IITs, NITs, IIITs
JEE Main 2025: BTech Information Technology cut-offs at NITs; know opening, closing ranks
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now