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\small \text { If } x^2+y^2=1 \text { then }

Option: 1

\mathrm{yy}^{\prime \prime}-2\left(\mathrm{y}^{\prime}\right)+1=0


Option: 2

y y^{\prime}+\left(y^{\prime}\right)^2+1=0


Option: 3

y y^{\prime}-\left(y^{\prime}\right)^2-1=0


Option: 4

y^{\prime \prime}+2\left(y^{\prime}\right)^2+1=0


Answers (1)

best_answer

Given equation is  x^2+y^2=1

Differentiating with respect to x
\begin{array}{ll} & 2 x+2 y y^{\prime}=0 \\ \text { or } \quad & x+y y^{\prime}=0 \end{array}

Again differentiating with respect to x  we have 

\begin{gathered} 1+y^{\prime \prime}+y^{\prime} y^{\prime}=0 \\ \text { or } \quad y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0 \end{gathered}
 

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Rishi

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